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無馬拐角和數獨(骨灰級) https://gridpuzzle.com/anti-knight-vudoku/n528r

#n528r的最新成績列表

In
Investing há um segundo
5'37''
Be
Benjamin 17 minutos atrás
6'4''
gu
guest 29 minutos atrás
6'35''
an
anonymous 23 minutos atrás
13'4''
El
Electricity 53 minutos atrás
7'0''
gu
guest 39 minutos atrás
5'9''
an
anonymous 21 minutos atrás
4'8''
re
restoration há uma hora
14'34''
br
brother há uma hora
19'31''
te
teriyaki há uma hora
11'40''

無馬拐角和數獨的最新成績列表

re
repair 完成 題ID#j8zq4;
17'8''
ch
chocolate 完成 題ID#qz1dq;
9'23''
Pr
Prestashop 完成 題ID#m9qmg;
12'33''
br
brother 完成 題ID#x87wx;
13'50''
fr
freelance 完成 題ID#zgyqy;
9'9''
Ja
James 完成 題ID#1y9k6;
11'30''
se
sell cash 完成 題ID#m9qmg;
10'25''
Re
Recovery 完成 題ID#gwqz2;
5'54''
an
anonymous 完成 題ID#206ky;
17'56''
mo
mortgage 完成 題ID#ppm6j;
19'51''

如何玩無馬拐角和數獨

無馬拐角和數獨規則

  • 將1~9填入空格內,使行、列及九宮格內均無重複數。

  • 每個拐角(彎三)的格子中(灰色的折線)必有有2個數加起來等於另一個數,但無順序要求。

  • 非全標。

  • 無馬規則:任意數字與其馬步格數字不重複

拐角數獨,每個拐角(彎三)的格子中(灰色的折線)必有有2個數加起來等於另一個數,但無順序要求。非全標。

無馬拐角和數獨 = 拐角和數獨 + 無馬數獨

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