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無馬拐角和數獨(高級) https://gridpuzzle.com/anti-knight-vudoku/ek4e4

#ek4e4的最新成績列表

gu
guest há um segundo
8'36''
gu
guest 6 minutos atrás
12'43''
wa
warranty 16 minutos atrás
17'12''
yo
youtube 13 minutos atrás
19'58''
Li
Liam 34 minutos atrás
3'41''
la
lawyer 29 minutos atrás
3'31''
Ab
Abigail 53 minutos atrás
17'50''
Do
Donate há uma hora
13'53''
cr
credit 2 horas atrás
6'2''
in
injury há uma hora
19'16''

無馬拐角和數獨的最新成績列表

In
Investing 完成 題ID#l5k6r;
6'7''
an
anonymous 完成 題ID#l8zv4;
14'48''
sp
specialist 完成 題ID#o6pvj;
7'4''
ch
chocolate 完成 題ID#3e14k;
12'51''
gu
guest 完成 題ID#lrw61;
5'47''
gu
guest 完成 題ID#l5p0r;
7'1''
gu
guest 完成 題ID#31q19;
11'37''
Cl
Claim 完成 題ID#l2xzd;
17'9''
ov
overtons 完成 題ID#lxzk7;
14'58''
gu
guest 完成 題ID#3wrdy;
10'45''

如何玩無馬拐角和數獨

無馬拐角和數獨規則

  • 將1~9填入空格內,使行、列及九宮格內均無重複數。

  • 每個拐角(彎三)的格子中(灰色的折線)必有有2個數加起來等於另一個數,但無順序要求。

  • 非全標。

  • 無馬規則:任意數字與其馬步格數字不重複

拐角數獨,每個拐角(彎三)的格子中(灰色的折線)必有有2個數加起來等於另一個數,但無順序要求。非全標。

無馬拐角和數獨 = 拐角和數獨 + 無馬數獨

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